If a particle moves from point P (2,3,5) to point Q (3,4,5). Its displacement vector be

$^i +^j + 10^k$

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$^i +^j + 5^k$

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$^i +^j$

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$2^i + 4^j + 6^k$

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Solution

The correct option is C
$^i +^j$

Displacement vector $¯ r = Δ x^i + Δ y^j + Δ z^k$
$= (3 - 2)^i + (4 - 3)^j + (5 - 5)^k =^i +^j$ .

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Similar questions

If a displacement vector of $A B$ is $^i +^j + 2^k$ and point $A$ having a position vector $2^i + 5^j + 6^k$ , then find the position vector of $B$ ?

\to r =^i - 2^j +^k

\to p = 2^i -^j +^k

2^i +^j + 3^k

2^i -^j +^k

\to F = (^i + 2^j + 3^k) N

{\to r}_{1} =^i +^j +^k

{\to r}_{1} =^i -^j - 2^k

The vector joining the points A (2, – 3, 1) and B (1, – 2, – 5) directed from B to A is:

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