If a particle moving in a straight line which has slope $4$ and passes through $(4, - 3)$ , then, the equation of the motion is

y - 4 x - 19 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y - 4 x + 19 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y + 4 x + 19 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y + 4 x - 19 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $y - 4 x + 19 = 0$
Given, slope of the line is $4$ and it passes through the point $(4, - 3)$
The equation of the motion is given as
$y - y_{1} = m (x - x_{1})$
$\Rightarrow y - (- 3) = 4 (x - 4)$
$\Rightarrow y = 4 x - 16 - 3$
$\Rightarrow y - 4 x + 19 = 0$

Suggest Corrections

Similar questions

4

(4, - 3)

(4, - 1)

\frac{1}{4}

\frac{2}{3}

(5, - 4)

(5, 7)

\frac{3}{4}

Join BYJU'S Learning Program