Question

If a particle moving in a straight line which has slope $4$ and passes through $(4,-3)$, then, the equation of the motion is

• A. $y-4x-19=0$
• B. $y-4x+19=0$
• C. $y+4x+19=0$
• D. $y+4x-19=0$

Answer 1

The correct option is B $y-4x+19=0$

Given, slope of the line is $4$ and it passes through the point $(4,-3)$
The equation of the motion is given as
$y-y_1=m(x-x_1)$
$\Rightarrow y-(-3)=4(x-4)$
$\Rightarrow y=4x-16-3$
$\Rightarrow y-4x+19=0$