If a particle of charge −0.2mC were placed at a certain location in an electric field, the magnitude of the electric force it would feel is 1N. Find out the magnitude of the electric field at this location? (1mC=10−3C)
A
2,000N/C
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B
5,000N/C
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C
20,000N/C
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D
50,000N/C
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E
500,000N/C
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Solution
The correct option is A5,000N/C Electric force, F=qE
So, magnitude of field |E|=|Fq|=|1−0.2×10−3|=5000N/C