If a particle of mass $m$ is moving in a horizontal circle of radius $r$ with a centripetal force $(1 / r^{2})$ , the total energy is:

(1 / 2 r)

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(1 / r)

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(2 / r)

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(4 / r)

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Solution

The correct option is B $(1 / 2 r)$
Centripetal force: $\frac{m v^{2}}{r} = \frac{1}{r^{2}}$

$\Rightarrow m v^{2} = \frac{1}{r}$
Total energy $= \frac{1}{2} m v^{2} = (\frac{1}{2 r})$

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (1/r2) , the total energy is:

The correct option is B (1/2r)Centripetal force: mv2r=1r2 ⇒mv2=1rTotal energy =12mv2=(12r)

If a particle of mass $m$ is moving in a horizontal circle of radius $r$ with a centripetal force $(1 / r^{2})$ , the total energy is:

The correct option is B $(1 / 2 r)$
Centripetal force: $\frac{m v^{2}}{r} = \frac{1}{r^{2}}$

$\Rightarrow m v^{2} = \frac{1}{r}$
Total energy $= \frac{1}{2} m v^{2} = (\frac{1}{2 r})$