If a = percentage drop in BSE sensex in eighth period and b = percentage increase in NSE sensex in fourth period, then what will be the relationship between a and b?

a < b

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a > b

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a = b

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None of these

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Solution

The correct option is B
a > b

$a = \frac{4471 - 4290}{4470} \times 100 = 4.02 % b = \frac{1290 - 1250}{1250} \times 100 = 3.2 % Hence a > b .$

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If a = percentage drop in BSE sensex in eighth period and b = percentage increase in NSE sensex in fourth period, then what will be the relationship between a and b?

The correct option is B a > b a=4471−42904470×100=4.02%b=1290−12501250×100=3.2%Hence a>b.

The correct option is B
a > b

$a = \frac{4471 - 4290}{4470} \times 100 = 4.02 % b = \frac{1290 - 1250}{1250} \times 100 = 3.2 % Hence a > b .$