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Question

If A=π/6 and B=π/3, then which of the following is/are correct?
1. sinA+sinB=cosA+cosB
2. tanA+tanB=cotA+cotB
Select the correct answer using the code given below

A
1 only
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B
2 only
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C
Both 1 and 2
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D
Neither 1 and 2
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Solution

The correct option is D Both 1 and 2
For (1)LHS=sinπ6+sinπ3=12+32
RHS=cosπ6+cosπ3=32+12
LHS=RHS Hence true.
For (2)=LHS=tanπ6+tanπ3=13+3
RHS=cotπ6+tanπ3=3+13
LHS=RHS Hence true.
Hence both (1) and (2) are correct.

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