If A=π/6 and B=π/3, then which of the following is/are correct? 1. sinA+sinB=cosA+cosB 2. tanA+tanB=cotA+cotB Select the correct answer using the code given below
A
1 only
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B
2 only
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C
Both 1 and 2
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D
Neither 1 and 2
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Solution
The correct option is D Both 1 and 2 For (1)LHS=sinπ6+sinπ3=12+√32 RHS=cosπ6+cosπ3=√32+12 LHS=RHS Hence true. For (2)=LHS=tanπ6+tanπ3=1√3+√3 RHS=cotπ6+tanπ3=√3+1√3 LHS=RHS Hence true. Hence both (1) and (2) are correct.