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Byju's Answer
Standard V
Mathematics
Frequency
If a pipe res...
Question
If a pipe resonates with sound waves of frequency 135 Hz and also 165 Hz but not with any wave of frequency intermediate between these two, then what is frequency of fundamental tone
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Solution
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135
,
165
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135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
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135
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×
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=
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135
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3
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=
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×
11
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135
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165
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135
,
165
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=
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×
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×
3
×
3
165
=
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×
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×
11
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135
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165
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135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
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135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
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O
15
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135
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165
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L
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A
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135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
S
O
15
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H
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C
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135
,
165
H
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L
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A
S
T
C
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P
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135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
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15
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135
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165
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L
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A
S
T
C
O
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M
O
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M
U
L
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I
P
L
E
O
F
135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
S
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15
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135
,
165
H
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g
L
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A
S
T
C
O
M
M
O
N
M
U
L
T
I
P
L
E
O
F
135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
S
O
15
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135
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165
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L
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A
S
T
C
O
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M
O
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L
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L
E
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F
135
,
165
135
=
5
×
3
×
3
×
3
165
=
5
×
3
×
11
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15
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Suggest Corrections
0
Similar questions
Q.
A pipe closed at one end and open at the other end resonates with a sound of frequency
135
H
z
and also with
165
H
z
, but not at any other frequency intermediate between these two. Then, the frequency of the fundamental note of the pipe is:
Q.
An organ pipe of cross-sectional area
100
c
m
2
resonates with a tuning fork of frequency
1000
H
z
in fundamental tone. The minimum volume of water to be drained so the pipe again resonates with the same tuning fork is (Take velocity of wave +
320
m
s
−
1
)
Q.
A
75
c
m
string fixed at both ends produces resonant frequencies of
384
H
z
and
288
H
z
without there being any other resonant frequency between these two. Wave speed for the string is :
Q.
The frequency of fundamental tone in an open pipe of length of
0.48
m is
320
Hz. Speed of sound is
320
m/sec. Frequency of fundamental tone in closed organ pipe will be
Q.
Fundamental frequency of pipe is
100
Hz and other two frequencies are
300
Hz and
500
Hz, then.
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