Question

If a plane passes through intersection of planes $2x-y-4=0$ and $y+2z-4=0$ and also passes through the point $(1,1,0)$. Then the equation of plane is

• A. $x-y-z=0$
• B. $2x-z=0$`
• C. $x+2z-1=0$
• D. $x-z-1=0$

Answer 1

Answer: (A)

$x-y-z=0$

$P_1+\lambda P_2=0$
$(2x-y-4)+\lambda (y+2z-4)=0$
it passes through $(1,1,0)$
$\Rightarrow 1+\lambda =0\Rightarrow \lambda =-1$
equation of plane is $x-y-z=0$