If a plant cell-s - p -2 bars and its - S -3-5 bars- what is the resulting - W -A- 0B- -1-5 barsC- 1-5 barsD- 5-5 bars

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Formula for Water Potential

If a plant ce...

Question

If a plant cell’s 𝜳p = 2 bars and its 𝜳s = -3.5 bars, what is the resulting 𝜳w?

0.0

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-1.5 bars

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1.5 bars

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5.5 bars

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Solution

The correct option is B -1.5 bars
𝜳s (solute potential or osmotic potential) is the magnitude of decrease of water potential with respect to that of pure water due to the dissolution of a solute.

𝜳p (pressure potential also called as turgor pressure or turgor potential) is the pressure exerted by the swelling protoplast on its walls due to the osmotic entry of water into it.

𝜳w (water potential) is the difference in potential of water in a system over its pure state at the same temperature and pressure. The water potential of pure water is zero and it is negative for any solution.

𝜳w = 𝜳p + 𝜳s = 2 bars + (-3.5 bars)
= -1.5 bars.

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Formula for Water Potential

Standard XII Biology

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