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Question

If A+C=B, then tanAtanBtanC=


A

tanAtanB+tanC

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B

tanBā€“tanCā€“tanA

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C

tanA+tanCā€“tanB

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D

-(tanAtanB+tanC)

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Solution

The correct option is B

tanBā€“tanCā€“tanA


Finding the value of tanAtanBtanC :

Given, A+C=B

Apply ā€œtanā€on both sides,

tan(A+C)=tanB

ā‡’(tanA+tanC)/(1ā€“tanAtanC)=tanBāˆµtanA+B=(tanA+tanB)/(1ā€“tanAtanB)

tanA+tanC=tanB(1ā€“tanAtanC)

tanA+tanC=tanBā€“tanAtanBtanC

āˆ“tanAtanBtanC=tanBā€“tanAā€“tanC

Hence, option (B) is correct.


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