If a point P(x,y) moves along the ellipse x225+y216=1 and if C is the centre of the ellipse, then, 4 max{CP} + 5 min{CP}=
40
Given ellipse is x225+y216=1
Here, a =5 and b =4
Max{CP} is the maximum distance from the centre to a point on the ellipse. It is equal to the length of the semi-major axis (a).
Similarly, Min {CP} is equal to the length of the semi-minor axis (b).
4 max{CP} + 5 min{CP}= 4a+5b
=4×5+5×4=40