If a polyhedron has 6 faces and 8 vertices, then it has
12
Given Vertices (V) = 8 ,Faces (F) = 6 , Let the number of edges be E
V+F-E = 2 ( Euler's formula)
Hence 8 + 6 - E = 2
14 - E = 2
-E = -12
E = 12
Hence If a polyhedron has 6 faces and 8 vertices, then it has 12 edges