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Strength of Materials

Plane of Maximum Shear Stress

If a prismati...

Question

If a prismatic member having area of cross-section A is subjected to a tensile load P, then the maximum shear stress and its inclination with the direction of load will be

A

\frac{P}{A} a n d 45 °

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B

\frac{2 P}{A} a n d 45 °

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C

\frac{P}{2 A} a n d 45 °

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D

\frac{P}{A} a n d 60 °

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Solution

The correct option is C $\frac{P}{2 A} a n d 45 °$
Maximum shear stress $= \frac{(P / A) + 0}{2} = \frac{P}{2 A}$

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