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Introduction to Projectile Motion

If a projecti...

Question

If a projectile is fired with an initial velocity $u$ at an angle $θ$ from the horizontal, for what time does it remain in the air?

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Solution

Vertical component of initial velocity, $u_{y} = u s i n θ$
At the highest point, vertical component of velocity will become zero.
From the first equation of motion, $v = u + a t \Rightarrow 0 = u_{y} - g t \Rightarrow 0 = u s i n θ - g t \Rightarrow t = \frac{u s i n θ}{g}$
$∴$ Time of flight, $T = 2 t = \frac{2 u s i n θ}{g}$

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