If a projectile is projected an angle $30^{\circ}$ with respect to the horizontal with an initial velocity 4 m/s, range of projectile is

1.384 m

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1.26 m

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1.13 m

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0.86 m

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Solution

The correct option is A 1.384 m
$R = \frac{u^{2} s i n 2 θ}{g}$
$= \frac{16 s i n 60^{\circ}}{10}$
$= 1.6 \times \frac{\sqrt{3}}{2}$
$= 1.39 m$

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If a projectile is projected an angle 30∘ with respect to the horizontal with an initial velocity 4 m/s, range of projectile is

The correct option is A 1.384 mR=u2sin2θg =16sin60∘10 =1.6×√32 =1.39m

If a projectile is projected an angle $30^{\circ}$ with respect to the horizontal with an initial velocity 4 m/s, range of projectile is

The correct option is A 1.384 m
$R = \frac{u^{2} s i n 2 θ}{g}$
$= \frac{16 s i n 60^{\circ}}{10}$
$= 1.6 \times \frac{\sqrt{3}}{2}$
$= 1.39 m$