If a proton and an electron have the same de Broglie wavelength, then:
A
kinetic energy of electron < kinetic energy of proton
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B
kinetic energy of electron = kinetic energy of proton
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C
momentum of electron = momentum of proton
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D
momentum of electron < momentum of proton
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Solution
The correct option is C momentum of electron = momentum of proton de Broglie wavelength, λ=hp where p is the momentum of the particle For electron, λe=hpe For proton, λp=hPp As λe=λp⇒Pp=Pp or Momentum of electron = Momentum of proton