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Question

If a proton and an electron have the same de Broglie wavelength, then:

A
kinetic energy of electron < kinetic energy of proton
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B
kinetic energy of electron = kinetic energy of proton
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C
momentum of electron = momentum of proton
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D
momentum of electron < momentum of proton
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Solution

The correct option is C momentum of electron = momentum of proton
de Broglie wavelength, λ=hp where p is the momentum of the particle For electron, λe=hpe
For proton, λp=hPp
As λe=λpPp=Pp
or Momentum of electron = Momentum of proton

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