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Question

If Ar=cosπ3r+isinπ3r, then the value of A1A2A3A is (where i=1)

A
1
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B
i
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C
1
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D
i
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Solution

The correct option is B i
Ar=cosπ3r+isinπ3rAr=eiπ3r

Now, A1A2A3A
=eiπ3eiπ32eiπ33=expiπ13113=eiπ2=i

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