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Byju's Answer
Standard XII
Mathematics
Standard Deviation
If a random v...
Question
If a random variable X follows a binomial distribution with mean 3 and variance 3/2, find P (X ≤ 5).
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Solution
Mean
(
n
p
)
=
3
and
variance
(
n
p
q
)
=
3
2
∴
q
=
1
2
and
p
=
1
-
1
2
n
=
Mean
p
⇒
n
=
6
Hence
,
the
distribution
is
given
by
P
(
X
=
r
)
=
C
r
6
1
2
r
1
2
6
-
r
,
r
=
0
,
1
,
2
.
.
.
6
=
C
r
6
2
6
∴
P
(
X
≤
5
)
=
1
-
P
(
X
=
6
)
=
1
-
1
64
=
63
64
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