If a random variable X has the following probability distribution-X- 0 1 1 2 3 x 15 310 25PX- 110Then- EX20

For random variable X nbsp; X P(X) X2 0 15 0 1 310 ...

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Conditional Probability

If a random v...

Question

If a random variable X has the following probability distribution:
X: 0 1 2 3
P(X): $\frac{1}{5} \frac{3}{10} \frac{2}{5} \frac{1}{10}$
Then, E(X²) =______________.

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X

X=x	0	1	2	3	4	5	6	7
P(X=x)	$0$	$k$	$2 k$	$2 k$	$3 k$	$k^{2}$	$2 k^{2}$	$7 k^{2} + k$

k

P (0 < X < 5)

$X = x$	$- 2$	$- 1$	$0$	$1$	$2$	$3$
$P (x)$	$0.1$	$0.1$	$0.2$	$0.2$	$0.3$	$0.1$

E (x) =

X

$X = x$	$- 2$	$- 1$	$0$	$1$	$2$	$3$
$P (x)$	$\frac{1}{10}$	$K$	$\frac{1}{5}$	$2 K$	$\frac{3}{10}$	$K$

X

10 k

$X$	$- 2$	$- 1$	$0$	$1$	$2$	$3$
$P (X)$	$0.1$	$k$	$0.2$	$2 k$	$0.3$	$k$

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