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Question

If a ray is incident on a parabolic mirror y2=4x along a line y=6 as shown, then what is the equation of the line along which the reflected ray travels?



A
9y=4x+18
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B
8y=6x6
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C
3y=7x+13
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D
2x+3y=19
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Solution

The correct option is B 8y=6x6
In a concave mirror, When the incident is parallel to principal axis, then the reflected ray passes through the principal focus.

At the point of incidence, y=6x=9

From the parabola equation y2=4ax, focus is at (1,0)

So the reflected light must pass through (1,0) and (9,6)

Therefore, from straight line equation, (y0)=6091(x1)

we get, 8y=6x6

Hence, option (b) is correct.

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