If a ray of light passing through (2,2) reflects on the x−axis at a point P and the reflected ray passes through the point (6,5), then the co-ordinates P is
A
(137,0)
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B
(227,0)
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C
(257,0)
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D
(277,0)
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Solution
The correct option is B(227,0) Let P(h,0) and PN be normal at P ∠APN=∠NPB=θ
So, we get
Slope of PB=tan(90∘−θ) ⇒5−06−h=cotθ⇒56−h=cotθ⋯(1)
And
Slope of AP=tan(90+θ) ⇒2−02−h=−cotθ⇒22−h=−cotθ
Using equation (1), we get ⇒22−h=−(56−h)⇒12−2h=−10+5h⇒h=227