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Question

If a ray of light passing through (2,2) reflects on the xaxis at a point P and the reflected ray passes through the point (6,5), then the co-ordinates P is

A
(137,0)
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B
(227,0)
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C
(257,0)
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D
(277,0)
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Solution

The correct option is B (227,0)
Let P(h,0) and PN be normal at P
APN=NPB=θ


So, we get
Slope of PB=tan(90θ)
506h=cotθ56h=cotθ(1)
And
Slope of AP=tan(90+θ)
202h=cotθ22h=cotθ
Using equation (1), we get
22h=(56h)122h=10+5hh=227

Hence, the coordinates of P is (227,0)

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