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Meter Bridge

If a resistan...

Question

If a resistance $5 Ω$ is connected in the left gap of a meter bridge and $15 Ω$ in the other gap then position of balancing point is

A

10 cm

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B

20 cm

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C

25 cm

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D

75 cm

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Solution

The correct option is C 25 cm
Consider the figure , it is given that $R = 5 o h m$ and $S = 15 o h m$
Now, at the balance point the circuit will be like a Wheatstone bridge .
That is,

$R / S = l_{1} / (100 - l_{1})$

$5 / 15 = l_{1} / (100 - l_{1})$

$4 * l_{1} = 100$
$l_{1} = 25 c m$

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