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Question

If a root of the equation x2+px+12=0 is 4, while the roots of the equation x2+px+q=0 are same, then the value of q will be

A
4
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B
4/49
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C
49/4
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D
None of these
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Solution

The correct option is C 49/4
Let's put x=4 in x2+px+12=0, which gets us p=7
Now second equation x2+px+q=0 have equal roots.
Let the root be r.
Sum of roots: r+r=p,
Product of roots: r2=q
Therefore p2=4qq=494

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