If a root to the given equation $a (b - c) x^{2} + b (c - a) x + c (a - b) = 0$ is 1, then the other will be

$\frac{c (a - b)}{a (b - c)}$

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$\frac{a (b - c)}{b (c - a)}$

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None of these

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$\frac{a (c - a)}{a (b - c)}$

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Solution

The correct option is A
$\frac{c (a - b)}{a (b - c)}$

Let $α$ = 1 and the other root is $β$ , then product of roots 1.

$β = \frac{c (a - b)}{a (b - c)}$

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Similar questions

a (b - c) x^{2} + b (c - a) x + c (a - b) = 0

1

If a root to the given equation a $a (b - c) x^{2} + b (c - a) x + c (a - b) = 0$ is 1, then the other will be

a (b - c) x^{2} + b (c - a) x + c (a - b) = 0

s e c θ + t a n θ = 1

a (b - c) x^{2} + b (c - a) x + c (a - b) = 0

a (b - c) x^{2} + b (c - a) x + c (a - b) = 0

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