If a row can fit 6 balls, arrange 13 balls in a box.

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Solution

The correct option is B
12 balls $\div$ 6 = 2 rows
3rd row will have 1 ungrouped ball.
The correct way of arranging the balls in the box:

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If a row can fit 6 balls, arrange 13 balls in a box.

The correct option is B 12 balls ÷ 6 = 2 rows 3rd row will have 1 ungrouped ball. The correct way of arranging the balls in the box:

The correct option is B
12 balls $\div$ 6 = 2 rows
3rd row will have 1 ungrouped ball.
The correct way of arranging the balls in the box: