Question

If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the density of the water is $1\times {10}^{3}kg/m^3$ and $g=10m/s^2$, then the volume elasticity in $n/m^2$ will be

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

$K=\frac{△P}{\frac{△V}{V}}=\frac{h\rho g}{\frac{△V}{V}}=\frac{200\times {10}^3\times 10}{\frac{0.1}{100}}=2\times {10}^9$