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Standard XII

Physics

Bulk Modulus

If a rubber b...

Question

If a rubber ball is taken at the depth of $200 m$ in a pool, its voulme decreases by $0.1 %$ . If the density of the water is $1 \times 10^{3} k g / m^{3}$ and $g = 10 m / s^{2}$ , then the volume elasticity in $N / m^{2}$ will be

10^{8}

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2 \times 10^{8}

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10^{9}

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2 \times 10^{9}

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Solution

The correct option is C $2 \times 10^{9}$
$K = \frac{Δ P}{Δ V / V} = \frac{h p g}{Δ V / V} = \frac{200 \times 10^{3} \times 10}{0.1 \times 100} = 2 \times 10^{9}$

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If a rubber ball is taken at the depth of 200 m in a pool, its volume decreases by 0.1%. If the density of the water is $1 \times 10^{3} k g / m^{3}$ and $g = 10 m / s^{2}$ , then the volume elasticity in $n / m^{2}$ will be

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If a rubber ball is taken at the depth of 200m in a pool, its voulme decreases by 0.1%. If the density of the water is 1×103kg/m3 and g=10m/s2, then the volume elasticity in N/m2 will be

The correct option is C 2×109K=ΔPΔV/V=hpgΔV/V=200×103×100.1×100=2×109

If a rubber ball is taken at the depth of $200 m$ in a pool, its voulme decreases by $0.1 %$ . If the density of the water is $1 \times 10^{3} k g / m^{3}$ and $g = 10 m / s^{2}$ , then the volume elasticity in $N / m^{2}$ will be

The correct option is C $2 \times 10^{9}$
$K = \frac{Δ P}{Δ V / V} = \frac{h p g}{Δ V / V} = \frac{200 \times 10^{3} \times 10}{0.1 \times 100} = 2 \times 10^{9}$