If a sec - - b tan - - 1 and a2 sec2 - - b2 tan2 - - 5- find a2b2 - 4a2-

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If a sec θ ...

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If $a s e c θ + b t a n θ = 1$ and $a^{2} s e c^{2} θ - b^{2} t a n^{2} θ = 5$ , find $a^{2} b^{2} + 4 a^{2}$ .

9 b^{2}

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\frac{9}{a^{2}}

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\frac{- 2}{b}

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a sec θ + b tan θ = 1

a^{2} {sec}^{2} θ - b^{2} {tan}^{2} θ

= 5

a^{2} b^{2} + 4 a^{2} =

a sec θ + b tan θ = 1, a^{2} {sec}^{2} θ - b^{2} {tan}^{2} θ = 5

a^{2} (b^{2} + 4) =

If x = asecθ + btanθ and y = atanθ + bsecθ, then, x² – y² = a² – b²

If $x = a s e c θ + b t a n θ$ and $y = a t a n θ + b s e c θ$ , prove that

$(x^{2} - y^{2}) = (a^{2} - b^{2})$ .

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