Question

If a semiconductor has an intrinsic carrier concentration of $1.41\times {10}^{16}/m^3$, when doped with ${10}^{21}/m^3$ phosphorous atoms, then the concentration of $holes/m^3$ at room temperature will be :

• A. $2\times {10}^{21}$
• B. $2\times {10}^{11}$
• C. $1.41\times {10}^{10}$
• D. $1.41\times {10}^{16}$

Answer 1

Answer: (D)

$1.41\times {10}^{16}$

Doping will increase the number of electrons only and not the holes. So, number of holes will be equal to number of intrinsic carrier concentration.
$=1.41\times {10}^{16}/m^3$