Question

If A = {set of squares of the first 3 natural numbers} and B = {set of cubes of the first 3 natural numbers}, then A and B are _____.

• A. Overlapping Sets
• B. Disjoint sets
• C. Equal Sets
• D. Equivalent sets

Answer 1

Answer: (A), (D)

The correct options are
A

Overlapping Sets

D

Equivalent sets

A = {set of squares of the first 3 natural numbers}

$A=\{1^2,2^2,3^2\}$

$\Rightarrow A=\{1,4,9\}$

B = {set of cubes of the first 3 natural numbers}

$B=\{1^3,2^3,3^3\}$

$B=\{1,8,27\}$

A and B have one common element.

Hence A and B are overlapping sets.

Also n(A) = n(B) = 3

Hence A and B are equivalent sets.