Question

If a shaft is turning at N r.p.m and the mean torque to which the shaft is subjected is T N-m, the power transmitted by the shaft in kW would be

• A. $\frac{2\pi NT}{45000}$
• B. $\frac{2\pi NT}{60000}$
• C. $\frac{2\pi NT}{30000}$
• D. $\frac{2\pi NT}{33000}$

Answer 1

The correct option is B $\frac{2\pi NT}{60000}$

Let mean torque to which the shaft is subjected to be T Nm

$\therefore$ Power transmitted = P = mean torque $\times$ angle turned per second

$=T\times \frac{N}{60}\times 2\pi Watts$

$=\frac{2\pi NT}{60,000}kW$