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Question

If a shunt of 110th of the coil resistance is applied to a moving coil galvanometer, its sensitivity becomes:

A
10 fold
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B
110 fold
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C
11 fold
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D
111 fold
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Solution

The correct option is D 111 fold
Given Rs=Rg10
Rg||Rs=RgRsRg+Rs
=Rg11

Let voltage across galvanometer be V
V=IgRg=I(Rg||Rs)
IgRg=IRg11
Ig=I11

Adding a shunt in parallel increases the range but reduces the sensitivity.

Sensitivity is defined as the ratio of deflection and current measured.
Original sensitivity is Si=θIg
New sensitivity is Sf=θI=θ11Ig

SfSi=111

622585_579985_ans_55a657de12da48dcacdb258472f44865.png

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