If a simple harmonic motion is represented by d2xdt2- x-0- Its time period is

The correct option is D 2π√(α) Option D is correct. #160; ...

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If a simple harmonic motion is represented by $\frac{d^{2} x}{d t^{2}} + α x = 0$ . Its time period is

2 π α

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2 π \sqrt{α}

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\frac{2 π}{α}

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\frac{2 π}{\sqrt{α}}

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If a simple harmonic motion is represented by $\frac{d^{2} x}{d t^{2}} + α x = 0$ its time period is

\frac{d^{2} x}{d t^{2}} + α x = 0

\frac{d^{2} x}{d t^{2}} + α x = 0

α

\frac{d^{2} x}{d t^{2}} + α x = 0

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