Question

If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0$m{s}^{-1}$ at any time, the angular frequency of the oscillator is equal to

• A. 10rads^-1
• B. 0.1rads^-1
• C. 100rads^-1
• D. rads^-1

Answer 1

The correct option is A

10rads^-1

$\omega =\sqrt{\frac{Acceleration}{Displacement}}=\sqrt{\frac{2.0}{0.02}}=10rad{s}^{-1}$