If a simple pendulum executing SHM falls freely along with the support, then

It does not oscillate at all

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Its periodic time increases

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Its periodic time decrease

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None of the above

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Solution

The correct option is A It does not oscillate at all
Time period of a simple pendulum,
$T = 2 π \sqrt{\frac{l}{g}}$
for freely falling system effective, $g = 0$
So, $T = \infty$
$∴$ pendulum does not oscillate at all.

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If a simple pendulum executing SHM falls freely along with the support, then

The correct option is A It does not oscillate at allTime period of a simple pendulum,T=2π√lgfor freely falling system effective, g=0So, T=∞∴ pendulum does not oscillate at all.

The correct option is A It does not oscillate at all
Time period of a simple pendulum,
$T = 2 π \sqrt{\frac{l}{g}}$
for freely falling system effective, $g = 0$
So, $T = \infty$
$∴$ pendulum does not oscillate at all.