Question

If a simple pendulum has a percentage error in length and time period 2% and 1% respectively . then what is the percentage error in ‘g’.

Answer 1

$$\begin{gathered} T=2\pi \sqrt{\frac{L}{g}} \\ g=\frac{T^2}{2\pi L} \\ \%erroring=2\times \%errorinT+\%errorinL=2\times 2\%+1\%=5\% \end{gathered}$$