If a simple pendulum is arranged in an artificial satellite its
a) time period becomes infinity
b) frequency becomes infinity
c) both time period and frequency become infinity
d) it does not oscillate

a and d are correct

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a and b are correct

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b, c are correct

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c, d are correct

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Solution

The correct option is A a and d are correct
in an artificial satellite $g_{e f f} = 0$
$\Rightarrow T = 2 π \sqrt{\frac{l}{g_{e f f}}}$ becomes infinity.
$∴$ it doesn't oscillate at all.

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If a simple pendulum is arranged in an artificial satellite its a) time period becomes infinity b) frequency becomes infinity c) both time period and frequency become infinity d) it does not oscillate

The correct option is A a and d are correctin an artificial satellite geff=0⇒T=2π√lgeff becomes infinity.∴ it doesn't oscillate at all.

If a simple pendulum is arranged in an artificial satellite its
a) time period becomes infinity
b) frequency becomes infinity
c) both time period and frequency become infinity
d) it does not oscillate

The correct option is A a and d are correct
in an artificial satellite $g_{e f f} = 0$
$\Rightarrow T = 2 π \sqrt{\frac{l}{g_{e f f}}}$ becomes infinity.
$∴$ it doesn't oscillate at all.