wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a=sin4(3π2α)+sin4(3π+α) and b=sin6(π2+α)+sin6(5πα), then the value of 3a2b is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1
a=sin4(3π2α)+sin4(3π+α)a=cos4α+sin4αa=12sin2αcos2αb=sin6(π2+α)+sin6(5πα)b=cos6α+sin6αb=13sin2αcos2α

Now,
3a2b=36sin2αcos2α2+6sin2αcos2α=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon