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B
0 < A≤1
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C
1 < 2A≤3
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D
Noneofthese
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Solution
The correct option is B 0 < A≤1 Given that A=sin8θ+cos14θ,
we know that (sin2θ)4≤sin2θand(cos2θ)7≤cos2θ
Adding, we that sin8θ+cos14θ≤1
or 0 < sin8θ+cos14θ≤1. Hence 0 < A≤1.