Question

$IfA=si{n}^8\theta +co{s}^{14}\theta$, then for all values of $\theta$

• A. A > 1
• B. A 1
• C. A < 1
• D. A 1

Answer 1

The correct option is D

A 1

$o\le si{n}^2\theta \le 1,ando\le co{s}^2\theta \le 1\Rightarrow o\le si{n}^8\theta \le si{n}^2\theta ando\le co{s}^{14}\theta \le co{s}^2\theta$

$\therefore$ 0 < $si{n}^8\theta +co{s}^{14}\theta \le si{n}^2\theta +co{s}^2\theta$

Hence o < A $\le$ 1