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Question

If asin(θ+α)=bsin(θ+α) show that cotθ=acosαbcosαbsinαasinα.

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Solution

from the above equation asin(θ+α)=bsin(θ+α)
asinθcosα+asinαcosθ=bsinθcosα+bsinθcosα
tanθtanα=baab
tanθ=sinα(ba)cosα(ab)
cotθ=acosαbcosαbsinαasinα

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