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Question

If a skater of weight 3 kg has initial speed 32 m/s and second one of weight 4 kg has 5 m/s. After collision, they have speed (couple) 5 m/s. Then the loss in K.E. is

A
48 J
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B
96 J
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C
Zero
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D
None of these
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Solution

The correct option is D None of these
Loss in K.E. = ( initial K.E. - final K.E. ) of system
ΔK=12m1u21+12m2u2212(m1+m2)V2

=123×(32)2+12×4×(5)212×(3+4)×(5)2

=986.5J

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