If a soil sample of weight 0.18 kg having a volume of $10^{- 4} m^{3}$ and dry unit weight of $1600 k g / m^{3}$ is mixed with 0.02kg of water then the water content in the sample will be

30%

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25%

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20%

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15%

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Solution

The correct option is B 25%
(b)
Dry weight of sample
$1600 \times 10^{- 4} = 0.16 k g$
Weight of water in soil before mixing additional quantity

= 0.18 - 0.16 = 0.02 kg

After mixing water the total quantity of water

= 0.02 + 0.02

= 0.04 kg water

$T h u s, w a t e r c o n t e n t = \frac{0.04}{0.16} \times 100 = 25 %$

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If a soil sample of weight 0.18 kg having a volume of 10−4m3 and dry unit weight of 1600kg/m3 is mixed with 0.02kg of water then the water content in the sample will be

The correct option is B 25%(b) Dry weight of sample 1600×10−4=0.16kg Weight of water in soil before mixing additional quantity = 0.18 - 0.16 = 0.02 kg After mixing water the total quantity of water = 0.02 + 0.02 = 0.04 kg water Thus, water content = 0.040.16×100=25%

If a soil sample of weight 0.18 kg having a volume of $10^{- 4} m^{3}$ and dry unit weight of $1600 k g / m^{3}$ is mixed with 0.02kg of water then the water content in the sample will be