If a solid piece of iron is in the form of a cuboid of dimensions 49 cm -33 cm - 24 cm is moulded to form a solid sphere- then the radius of the sphere is

The correct option is A 21 cmVolume of a Cubiod =lbh Volume of a Sphere 4/3π r^3 Volume of Cuboid = Volume of Sphere 49× 33× 24=4/3π ...

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Standard X

Mathematics

Surface area of Combination of solids

If a solid pi...

Question

If a solid piece of iron is in the form of a cuboid of dimensions $49$ cm $\times 33$ cm $\times 24$ cm is moulded to form a solid sphere, then the radius of the sphere is

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Solution

The correct option is A $21$ cm
Volume of a Cubiod $= l b h$
Volume of a Sphere $\frac{4}{3} π r^{3}$
Volume of Cuboid $=$ Volume of Sphere
$49 \times 33 \times 24 = \frac{4}{3} π r^{3}$
$r^{3} = 9261$
$r = 21$ cm
Hence, option A is correct.

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A solid piece of iron in the form of a cuboid of dimensions $49 c m \times 33 c m \times 24 c m$ , is moulded to form a solid sphere. Then, radius of the sphere is
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(B) 23 cm
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A solid piece of iron in the form of a cuboid of dimensions $(49 c m \times 33 c m \times 24 c m)$ is moulded to form a solid sphere. The radius of the sphere is

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49

\times

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\times

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(b) 28 cm

(c) 35 cm

(d) none of these

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is moulded into a sphere. The radius of the sphere is

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If a solid piece of iron is in the form of a cuboid of dimensions 49 cm ×33 cm ×24 cm is moulded to form a solid sphere, then the radius of the sphere is

The correct option is A 21 cmVolume of a Cubiod =lbhVolume of a Sphere 43πr3Volume of Cuboid = Volume of Sphere49×33×24=43πr3r3=9261r=21 cmHence, option A is correct.

If a solid piece of iron is in the form of a cuboid of dimensions $49$ cm $\times 33$ cm $\times 24$ cm is moulded to form a solid sphere, then the radius of the sphere is

The correct option is A $21$ cm
Volume of a Cubiod $= l b h$
Volume of a Sphere $\frac{4}{3} π r^{3}$
Volume of Cuboid $=$ Volume of Sphere
$49 \times 33 \times 24 = \frac{4}{3} π r^{3}$
$r^{3} = 9261$
$r = 21$ cm
Hence, option A is correct.