If a solution of a salt in dil. nitric acid silver nitrate is added, a pale yellow precipitate is obtained. If this precipitate is partly soluble in ${N H}_{4} O H$ , then the acid radical of the salt is :

chloride

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nitrate

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bromide

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sulphate

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Solution

The correct option is C bromide
${B r}^{(-)}_{(a q)} + A g {N O}_{3} (a q) ⟶ A g B r ↓ + {N O}_{3}^{-}$
(yellow ppt.)
$A g B r ↓ + {N H}_{4} O H ⟶ {[A g {({N H}_{3})}_{2}]}^{+} {B r}^{(-)}$
(partially
soluble)

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Similar questions

(N a X)

(H N O_{3})

(A g N O_{3})

N H_{4} O H

Identify the anion present in the salt on the basis of the reaction given below:

When silver nitrate solution is added to a salt solution, a white precipitate, insoluble in dilute nitric acid, is formed.

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