Question

If a speed of particle is doubled , then will the ratio of kinetic energy to its momentum?

Answer 1

Dear Student

Ratio of kinetic energy to momentum when velocity of particle is v
$\frac{K.E.}{P}=\frac{{\displaystyle \frac{1}{2}}m{v}^2}{mv}=\frac{1}{2}v$
Ratio of kinetic energy to momentum when velocity of particle is 2v
​$\frac{K.E.}{P}=\frac{{\displaystyle \frac{1}{2}}m{\left(2v\right)}^2}{2mv}=v$
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