Question

If a spoon of copper metal is placed in a solution of $FeS{O}_4$. What will be the correct observation?

• A. Copper is dissolved in $FeS{O}_4$ to give brown deposit.
• B. No reaction takes places.
• C. Iron is deposited on copper spoon.
• D. Both copper and iron are precipitated.

Answer 1

Answer: (B)

No reaction takes places.

Since the reduction potential of copper is higher than that of iron.

Therefore possible reaction is:

$C{u}^{2+}+Fe\to Cu+F{e}^{2+}$

But it is given that copper metal is placed in $FeS{O}_4$ or $F{e}^{2+}$ solution thus no reaction will occur.

$F{e}^{2+}+Cu\to NoReaction$