If a spring of spring constant k is divided into m equal parts, and all are connected in parallel, then the equivalent spring constant of the combination is
A
mk
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B
k
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C
m2k
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D
m2k
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Solution
The correct option is Cm2k Let us assume that the length of given spring be l
Then, on dividing it into m equal parts, the length of each new spring would be lm
Let spring constant of the new springs be k′ each
Then, we have k′×lm=kl⇒k′=mk
Since, all are connected in parallel, then equivalent spring constant would be keq=(mk+mk+mk⋅⋅⋅⋅⋅+mk)m times mk ⇒keq=m(mk)=m2k