If a=2√2i then which of the following is correct
a=1+i
1
None of these
We have a =√2i=√2(cosπ2+isinπ2)12=√2(eiπ2)12=√2eiπ4=√2(1√2+i√2i)=1+i Trick:Check with options.
If 1−ix1+ix=a+ib,then a2+b2=
If x = √2+√1, then the value of [x+1x] is ?